2x^-7x^2+3=0

Solution for 2x^-7x^2+3=0 equation:

2x^-7x^2+3=0

We add all the numbers together, and all the variables

-7x^2+2x+3=0

a = -7; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·(-7)·3
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{22}}{2*-7}=\frac{-2-2\sqrt{22}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{22}}{2*-7}=\frac{-2+2\sqrt{22}}{-14}
$